You really should by a book, or at least go to www.cisco.com and search for
some of these facts.
Anyway, the output you included means that in order to get to network
209.221.163.0, the data will be routed with the EIGRP routing protocol out
the Ethernet 0 interface of your router and head for the router with IP
address 63.249.3.9. That router might or might not be directly connected to
that network, but you can then telnet into 63.249.3.9 and look at that
routing table, and thereby get to your network.
Hth,
Ole
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Ole Drews Jensen
Systems Network Manager
CCNA, MCSE, MCP+I
RWR Enterprises, Inc.
[EMAIL PROTECTED]
http://www.oledrews.com/ccnp
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
NEED A JOB ???
http://www.oledrews.com/job
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
-----Original Message-----
From: Paver, Charles [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, January 16, 2001 7:45 AM
To: '[EMAIL PROTECTED]'
Subject: tcpip question
Again, the tcp/ip question
209.221.163.0/27 is subnetted, 1 subnets
D 209.221.163.0 [90/2221056] via 63.249.3.9, 13:31:00, Ethernet0
In this example I took off a router: the 209.221.163.0 is a network ip,
right? But what network, as in, where is the network--the router I am
accessing? I understand the 63.x.xx. is the next hop router, but is that
the origination point, of the destination point (the 209.x.x.x?) Thanks
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