<html><DIV> <P>Hi All,</P> <P> I'm working through as lab scanerio and I trying to understand; in what order does equal cost default routes(0.0.0.0/0) get added to the routing table. How is one default route made the primary over the other. "sh ip ospf data " and "sh ip ospf data ext" shows me the following. Looking at the database it would seem that the advertising router with the hightest address wins. This being the case is there a defined selection process?</P> <P><BR> Type-5 AS External Link States</P> <P>Link ID ADV Router Age Seq# Checksum Tag<BR>0.0.0.0 172.16.255.130 1138 0x80000BD6 0x5049 4<BR>0.0.0.0 172.116.200.1 721 0x800007FD 0x79B1 4</P> <P><BR> OSPF Router with ID (138.139.255.97) (Process ID 3475)</P> <P><BR> Type-5 AS External Link States</P> <P> Routing Bit Set on this LSA<BR> LS age: 1256<BR> Options: (No TOS-capability, DC)<BR> LS Type: AS External Link<BR> Link State ID: 0.0.0.0 (External Network Number )<BR> Advertising Router: 172.16.255.130<BR> LS Seq Number: 80000BD6<BR> Checksum: 0x5049<BR> Length: 36<BR> Network Mask: /0<BR> Metric Type: 2 (Larger than any link state path)<BR> TOS: 0 <BR> Metric: 1 <BR> Forward Address: 0.0.0.0<BR> External Route Tag: 4</P> <P> Routing Bit Set on this LSA<BR> LS age: 838<BR> Options: (No TOS-capability, DC)<BR> LS Type: AS External Link<BR> Link State ID: 0.0.0.0 (External Network Number )<BR> Advertising Router: 172.18.200.1<BR> LS Seq Number: 800007FD<BR> Checksum: 0x79B1<BR> Length: 36<BR> Network Mask: /0<BR> Metric Type: 2 (Larger than any link state path)<BR> TOS: 0 <BR> Metric: 1 <BR> Forward Address: 0.0.0.0<BR> External Route Tag: 4</P> <P>TIA<BR>Nigel</P> <P> </P></DIV><br clear=all><hr>Get your FREE download of MSN Explorer at <a href="http://explorer.msn.com">http://explorer.msn.com</a><br></p></html> _________________________________ FAQ, list archives, and subscription info: http://www.groupstudy.com/list/cisco.html Report misconduct and Nondisclosure violations to [EMAIL PROTECTED]
