Try this ->

Look at the bits in the last octet

96   = 01100000
127 = 01111111

The common bits are the first three, so you want to mask it like this  ->
00011111  or, 31

65 = 01000001
95 = 01011111

The common bits are again the first bits, so again the mask is -> 00011111
or 31

So, your list should be be
    deny 171.17..2.96 0.0.0.31
     permit 172.17.2.64 0.0.0.31



----- Original Message -----
From: "jeongwoo park" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Friday, February 23, 2001 1:25 PM
Subject: Fw: A different Wildcard Mask [1:2082]


> Hi all.
> Can anyone clear this?
> thanks
> J
> ----- Original Message -----
> From: "V Cumbie" <[EMAIL PROTECTED]>
> Newsgroups: groupstudy.associate
> Sent: Wednesday, February 21, 2001 12:08 PM
> Subject: A different Wildcard Mask [1:2082]
>
>
> > Can you permit/deny only half of a subnet?  Here is my problem:
> >
> > Network: 171.17.2.64
> > Subnet mask: 255.255.255.192
> > Host range: 171.17.2.65 thru 171.17.2.126
> > Broadcast: 171.17.2.127
> >
> > I have to deny telnet from hosts 171.17.2.96 thru 171.17.2.126
> > and allow the remaining addresses (the lower half) 65 thru 95 complete
> > access.
> >
> > I can not figure out a wildcard mask for splitting the hosts in half; to
> > deny/permit one half of them.
> >
> > I would appreciate any help on this.
> >
> > V. Cumbie
> >
> >
> >
> >
> >
> > Message Posted at:
> > http://www.groupstudy.com/form/read.php?f=1&i=2082&t=2082
> > --------------------------------------------------
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>
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