Unless you use "ip subnet-zero" Then it starts with 172.16.0.0. ;^)
I agree though, either way you slice this, it's not a network address.
D.
At 05:38 PM 05/24/2001 -0400, Michael Bambic wrote:
>OK first of all 172.16.0.0/21 is actually 172.16.0.0 255.255.248.0
>Which means the network address are:
>172.16.8.0
>172.16.16.0
>172.16.24.0
>172.16.32.0
>172.16.40.0 etc. etc. going up by 8 in the 3rd octet until you hit
>172.16.248.0
>
>So the answer is no because 172.16.0.1 falls into the first invalid range
>which is 172.16.0.0 through 172.16.7.255.
>
>Hope that helps.
>
>Mike Bambic
>CCDP, CCNP, CCIE Written
>Looking for a job in Phoenix
>
>
>
>
>-----Original Message-----
>From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]On Behalf Of
>CCIE TB
>Sent: Thursday, May 24, 2001 1:50 PM
>To: [EMAIL PROTECTED]
>Subject: IP Address [7:5786]
>
>
>Hi Group members,
>
>I came across a question in a Transcender exam in which they give a network
>address as 172.16.0.1/21. This address is given by an ISP to your network.
>Is that address a possible network address? It looks to me as a host
>address. What I'm missing here?
>
>Regards to all
>
>Adia
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Darren S. Crawford
Network Systems Consultant
Lucent Technologies - Sacramento
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