easy going,... your mask is 29 bits long, this means: you have 3 bits left
to address host within this subnet. so there are 8 possibilities (2 to the
power of 3 (bits)) left for hosts.
the last three bits set to one will be the broadcast for this net, the bits
set to zero will be the segment itself. theoretical, they are forbidden to
use for host.
8 possibilities minus 2 "forbidden" are 6 hosts within this net.
the net is 213.13.184.184 /29, the first host will be 213.14.184.185 /29,
the last host will be 213.13.184.191 /29, the broadcast will be
213.13.184.192 /29
binary (last octet) 10111000 ->net, 11111000 ->mask, 10111001 ->first host,
10111110 ->last host, 10111111 ->broadcast
- use a subnetcalculator....
Message Posted at:
http://www.groupstudy.com/form/read.php?f=7&i=11906&t=11902
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