The /16 means that the network in the address given are the first 16 bits,
or in other words the first two octets. Therefore:
10.5.0.0/16 gives network 10.5
10.6.0.0/16 gives network 10.6
10.7.0.0/16 gives network 10.7
Since there are no table entries for network 10.7, it will use the default
route.
Hth,
Ole
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Ole Drews Jensen
Systems Network Manager
CCNA, MCSE, MCP+I
RWR Enterprises, Inc.
[EMAIL PROTECTED]
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-----Original Message-----
From: suleman ibrahim aboo [mailto:[EMAIL PROTECTED]]
Sent: Thursday, July 26, 2001 3:57 AM
To: [EMAIL PROTECTED]
Subject: classless routing [7:13847]
Can you please explain what would happen and why.
A router has ip classless enabled. It's routing table has entries for
10.5.0.0/16 and 10.6.0.0/16 and a default route 0.0.0.0. A packet arrives
for a destination on 10.7.0.0/16. Which route does it take ?
thanks in advance
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