I'm sure the folks at Sonic Rim and Kathy's Cottage ( to name a couple )
appreciate your using their space to illustrate your question ;->

I'll ignore the couple of typos in there. it's late.

you have an overlap in your first three subnets.

105.0/25 ( not /17 ) overlaps with 105.0/26 ( not 18 ) and 105.64/26

How many hosts do you need on each subnet? It is sometimes better to work
backwards from there.

Chuck


-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]On Behalf Of
Sarah Parker
Sent: Thursday, December 13, 2001 8:15 PM
To: [EMAIL PROTECTED]
Subject: Help with IP Addressing/VLSM- work project [7:29160]


Hello Everyone,

I am working on a small IP address project and trying
to figure out VLSM.

Since I am not very good and do not have much
experience with IP addressing, I wanted to send this
to make sure what I have is correct or if I am really
wrong on this one.
Thanks in advance for any feedback or corrections!!

This is a new network-
Current IP Address=65.85.105.0
Mask=255.255.255.0

I need a total of  5 subnets.

What I did
Took 65.85.105.0, 255.255.255.128 to subnet into  2
networks,
This gave me
Subnet 1= 65.85.105.0, hosts 1-126, broadcast  127
Subnet 2=65.85.105.128, hosts 129-254, broadcast 255

Took 65.85,105.128 255.255.255.192 to subnet into 4
subnets
This gave me
Subnet 1=65.85.105.0. hosts 1-62, broadcast 63
Subnet 2=65.85.105.64, hosts 54-126, broadcast 127
Subnet 3=65.85.105.128, hosts 129-190, broadcast 190
Subnet 4=65.85.105.192, hosts 193.254, broadcast 255

So this would give me to use on the network
1=65.85.105.0 255.255.255.128 (17 mask?)
2=65.85.105.0 255.255.255.192 (18 mask?)
3=65.85.105.64 255.255.255.192
4=65.85.105.128 255.255.255.192
5=65.85.105.192 255.255.255.192


Did I do this correctly? This is based on using subnet
zero.

I am using a public class A but for security reasons I
did change the actual real address.

Thanks again for everyones feedback.


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