I'll take another stab at an answer. Cisco Nuts wrote: > > Hello,If the requirement is to configure 30% of the bandwidth > on the > serial port (1.544MB) for ipx traffic, how much will that be?I > calculated > (1.544 X 1024)/(30/100)?
Your bandwidth is 1.544 x 1000 x 1000 = 1,544,000 bits per second. To get 30% of that multiply by .30. Don't divide! Hopefully that was a typo? :-) > Is this how it's done or is there a > right way to However, that is not how it's done. You configure custom queuing with a byte count, not a bps value. If you're queuing, then 100% of the bandwidth is in use, regardless of what the bandwidth is. Otherwise the packets would be going out right away without ending up in a queue. All you have told us is that IPX should use 30% of the bandwidth. So you want IPX to use 30 parts of the bandwidth and non-IPX protocols to use 70 parts of the bandwidth. You can simplify that. Divide them both by 10. So you want IPX to use 3 parts of the bandwidth and non-IPX protocols to use 7 parts of the bandwidth. Let's assume IPX is using 1500 byte packets, which it probably is. One solution would be to let IPX send 3 of these packets out. Then let other protocols send 7 1500 byte packets out. 3 x 1500 bytes = 4500 bytes 7 x 1500 bytes = 10500 bytes I can't remember the exact syntax, but you can look that up. :-) I think it would be something like this: queue-list 1 protocol ipx 1 queue-list 1 queue 1 byte-count 4500 queue-list 1 default 2 queue-list 1 queue 2 byte-count 10500 HTH. Priscilla > do this to get the actual value?Thank you.Sincerely,CN > > ------------------------------------------------------------------------ > > Add photos to your messages with MSN 8. Get 2 months FREE*. > > Message Posted at: http://www.groupstudy.com/form/read.php?f=7&i=63478&t=63448 -------------------------------------------------- FAQ, list archives, and subscription info: http://www.groupstudy.com/list/cisco.html Report misconduct and Nondisclosure violations to [EMAIL PROTECTED]
