Hello!

I try to make a system to run on i486. Because such systems were very
slow, I decided to build one on my AthlonXP-based machine (i686) and I
have already successfully built the temporary tools.

I came to conclusion that I can use chroot method for building the base
system but when I run configure for glibc in the ch. 10.7. I have the
following

> checking build system type... i686-pc-linux-gnu
> checking host system type... i686-pc-linux-gnu

<snip>

> checking whether 
> /tools/lib/gcc/i486-pc-linux-gnu/4.1.1/../../../../i486-pc-linux-gnu/bin/as 
> is GNU as... yes
> checking whether 
> /tools/lib/gcc/i486-pc-linux-gnu/4.1.1/../../../../i486-pc-linux-gnu/bin/ld 
> is GNU ld... yes

It seems strange for me. Glibc "guessed" that my system is i686 but it
is going to use the compiler/binutils for the i486 target.

So, my question are

1. Did I miss something when building the previous stages of the book?

2. Can I use the 1.x version of the book for such a build? Note, I'm
   going to build a system for running on i486 and I'm going to make
   the _whole_ build (cross-tools, tools, base, some other programs) on
   a i686 system.

3. If everything is correct then where glibc will use the values
   "i686-pc-linux-gnu"?

-- 
Nothing but perfection
pv
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