Hello,
I am writing a Makefile to build glibc in Chapter 10 of the CLFS guide. I
am trying to setup something like the following:
ARCH = `cut -d- -f1 <<< ${MACHTYPE}`
CONFIG_ENV = CFLAGS="-march=$(ARCH) -mtune=generic -g -O2"
When I am at the shell prompt and run this command, echo $MACHTYPE, the
result is i686-redhat-linux-gnu. When I run the Makefile to echo $(ARCH), I
receive this error:
echo `cut -d- -f1 <<< `
/bin/sh: command substitution: line 0: syntax error near unexpected token
`newline'
/bin/sh: command substitution: line 0: `cut -d- -f1 <<< '
I used a similar style way of defining ARCH when I built glibc for the
cross-tools, however in that case it was not MACHTYPE that was referenced,
but instead the CLFS_TARGET environment variable. How can I get this latest
Makefile to "see" MACHTYPE? I realize that MACHTYPE is not an environment
variable. Is there a work around (other than hard-coding)?
Thank you,
Dave
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