> (map #(fif even? (fn [x] (* 2 x))) [3 4]) Your fif returns a function. So probably what you wanted to do was: user=> (map (fif even? (fn [x] (* 2 x))) [3 4]) (nil 8) fif is returning an unnamed function which accepts one argument and can thus be mapped to [3 4]
#(...) creates an unnamed function, in your case it was creating a function with no arguments. So to use that syntax correctly you might do: (map #(if (even? %1) (* 2 %1)) [3 4]) The point of fif is to simplify the above, though I guess for this example it actually makes it longer :) You could have written fif as (defn fif [iff then & else] #(if (iff %1) (then %1) (if else ((first else) %1)))) Regards, Tim. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/clojure?hl=en -~----------~----~----~----~------~----~------~--~---
