I'm in the following situation:
(and '(true true))
;doesn't work
I tried apply, reduce, and a few other things. Reading the apidocs,
reduce is said to be the proper choice to compute a boolean from a
seq. But:
(reduce and '(true true))
;Exception: Can't take value of a macro: #'clojure.core/and
Also, the following isn't the solution:
(reduce 'and '(true false true))
;true
In any case, I think using reduce with "and" wouldn't be nice because
it won't return false as soon as it can like "and" does. Therefore, I
came up with the following working solution:
(defmacro and-booleans [logical-booleans-list]
`(and ~...@logical-booleans-list))
(and-booleans (true false true))
;false
But I wonder if I have overlooked something fundamental, either about
reduce or anything else.
Of course, I could have built my final boolean value imperatively, in
effect reimplementing "and" for lists as a function that wraps the
"ant" built-in macro. But I'm hoping to leave imperative programming
as much behing me as possible.
What would you consider the normal way of solving this small problem
of mine?
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