Talking about equality of:
user=> (= [1, 2] '(1, 2))
true
I also wondered if there could be something as "strict equal", which
returns true only if both the operands are equal and of the same type.
See JavaScript:
http://www.devguru.com/Technologies/ecmascript/quickref/comparison_operators.html
http://www.devguru.com/Technologies/ecmascript/quickref/javascript_index.html
Frantisek
On Jan 28, 9:17 pm, Cosmin Stejerean <cstejer...@gmail.com> wrote:
> On Wed, Jan 28, 2009 at 11:13 AM, Frantisek Sodomka <fsodo...@gmail.com>wrote:
>
> [...]
>
> Since this is correct:
>
> > user=> (= () [])
> > true
>
> > Shouldn't these be also 'true'?
> > user=> (= {} [])
> > false
> > user=> (= {} #{})
> > false
> > user=> (= {} ())
> > false
> > user=> (= #{} [])
> > false
> > user=> (= #{} ())
> > false
>
> Well, I'm not yet sure if I like it but lists and vectors that have
> identical elements in them appear to be equal, not just empty ones.
>
> user=> (= [1, 2] '(1, 2))
> true
>
> Since any list can be represented as an equivalent vector (and any vector as
> an equivalent list) I can imagine this making sense.
>
> user=> (apply list [1 2 1])
> (1 2 1)
> user=> (apply vector '(1 2 1))
> [1 2 1]
>
> But I don't see how this would ever apply to sets or maps so I don't see why
> empty sets and maps should be an exception.
>
> --
> Cosmin Stejereanhttp://offbytwo.com
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