On Feb 10, 11:18 pm, Mark Engelberg <mark.engelb...@gmail.com> wrote:
> I was the source of this error, and I agree that the behavior is an
> error. I missed the case of a negative divisor and a 0 remainder
> among my test cases for the mod function.
>
> Thanks for noticing and fixing the problem.
>
> Although Chouser's version is slightly more compact than Pratley's, I
> wonder if a multiplication followed by a single comparison to zero is
> a significantly more or less expensive operation than several
> comparisons to zero? My instinct is that multiplication is more
> expensive, but I haven't had a chance to really check.
Patch welcome, if you've all come to a conclusion.
Rich
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