Of course ;) Keep forgetting the obvious things.

On Sun, Feb 15, 2009 at 9:36 PM, Stuart Halloway
<stuart.hallo...@gmail.com>wrote:

>
> (map vector [1 2 3] ['a 'b 'c] ["cat" "dog" "bird"])
> -> ([1 a "cat"] [2 b "dog"] [3 c "bird"])
>
> > Actually something closer to your exact expression is this:
> >
> > (apply (partial map (fn [& rest] (apply vector rest))) [[1 2 3] ['a
> > 'b 'c] ["cat" "dog" "bird"]])
> >
> > On Sun, Feb 15, 2009 at 7:42 PM, David Nolen
> > <dnolen.li...@gmail.com> wrote:
> > (map (fn [& rest] (apply vector rest)) [1 2 3] ['a 'b 'c] ["cat"
> > "dog" "bird"])
> >
> >
> > On Sun, Feb 15, 2009 at 7:16 PM, samppi <rbysam...@gmail.com> wrote:
> >
> > What would I do if I wanted this:
> >
> > [[a0 a1 a2] [b0 b1 b2] ...] -> [[a0 b0 ...] [a1 b1 ...] [a2 b2 ...]]
> >
> > I could write a loop, I guess, but is there a nice, idiomatic,
> > functional way of doing this? I didn't spot a way in
> > clojure.contrib.seq-utils either.
> >
> >
> >
> >
> > >
>
>
> >
>

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