Don't try to force the destructuring DSL to do more than it was intended to
do. Just do it manually (or write a macro if you really insist):
(defn foo
[& args]
(let [ [a b c] (take 3 args)
mid3 (take 3 (drop 3 args))
[g h i] (drop 6 args) ]
(when (< 9 (count args))
(throw (IllegalArgumentException. (str "Too many args:" args))))))
(foo 1 2 3 4 5 6 7 8 9) => nil
(foo 1 2 3 4 5) => nil
(foo 1 2 3 4 5 6 7 8 9 10) => java.lang.IllegalArgumentException: Too
many args:(1 2 3 4 5 6 7 8 9 10),
On Wed, May 10, 2017 at 6:17 PM, Kevin Kleinfelter <
kleinfelter.gro...@gmail.com> wrote:
> Can I destructure a list, assigning the first and last few items
> individually, while putting several items from the middle into a list?
>
> I see that I can assign a list:
> (let [a '( 1 2 3 4)] ...)
>
> I can destructure the list as a whole:
> (let [[a b c d] '(1 2 3 4)] ...)
>
> I can destructure the list and bundle the TRAILING elements into a list:
> (let [[a & stuff] '(1 2 3 4)] ...))
>
> But suppose I had a list of 9 items and I wanted the first 3 individually,
> 3 in the MIDDLE as a list, and the last 3 individually. Something like:
> (let [[a b c & middle d e f] '( 1 2 3 4 5 6 7 8 9)] ...)
>
> How do I do that?
>
> Tnx.
>
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