So is it best practice to implement map in the deftype to make it spec-able? 
Are there examples somewhere that show how to do this in a canonical way?

If you want a `deftype` that is spec-able as a map, why not just use 
`defrecord`? Manually implementing the various map-related interfaces is a fair 
bit of boilerplate/work.

Sean Corfield -- (970) FOR-SEAN -- (904) 302-SEAN
An Architect's View -- http://corfield.org/

"If you're not annoying somebody, you're not really alive."
-- Margaret Atwood

________________________________
From: clojure@googlegroups.com <clojure@googlegroups.com> on behalf of 
markus.ag...@gmail.com <markus.ag...@gmail.com>
Sent: Wednesday, July 4, 2018 7:47:45 AM
To: Clojure
Subject: Re: How do I use spec and deftype together?

So is it best practice to implement map in the deftype to make it spec-able? 
Are there examples somewhere that show how to do this in a canonical way?

On Wednesday, July 4, 2018 at 12:51:29 PM UTC+2, Leon Grapenthin wrote:
Spec doesn't check object fields. The defrecord case works because defrecord 
implements map.

On Wednesday, July 4, 2018 at 12:47:26 PM UTC+2, markus...@gmail.com wrote:
The same question was asked on
https://clojurians-log.clojureverse.org/clojure-spec/2018-01-19
but I did not find an answer.

An example, where defrecord works fine but deftype fails:

(do
  (require '[clojure.spec.alpha :as s])
  (defprotocol Foo (foo [this]))
  (defrecord Bar [bar] Foo (foo [this] (.bar this)))
  (deftype   Baz [bar] Foo (foo [this] (.bar this)))
  (s/def ::bar number?)
  [(s/valid? (s/keys :req-un [::bar]) (->Bar 0))
   (s/valid? (s/keys :req-un [::bar]) (->Baz 0))]) ;[true false]

How do I have to change the last line so that it yields true as well?

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