I map produces a lazy sequence, time doesn't force it, if you wrap it in either a dorun or doall, you should get what you expect:
user> (time (map #(Thread/sleep %) '(1000 1000 1000))) "Elapsed time: 0.156 msecs" (nil nil nil) user> (time (doall (map #(Thread/sleep %) '(1000 1000 1000)))) "Elapsed time: 3000.383 msecs" (nil nil nil) user> I think that is what you're running into. Kyle On Sat, Jun 6, 2009 at 5:02 PM, artg <artgittle...@gmail.com> wrote: > > user=> (time (map answer '(500000 500000))) > "Elapsed time: 0.032826 msecs" > (392330 392711) > user=> (time (answer 500000)) > "Elapsed time: 6357.131423 msecs" > 392849 > > When I try to time 'map' it seems to return right away. How do I time > the full two executions of 'answer'? > > > > -- ------------------------------------------------------------------------------ kyle.bur...@gmail.com http://asymmetrical-view.com/ ------------------------------------------------------------------------------ --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en -~----------~----~----~----~------~----~------~--~---
