2009/7/17 Chouser <chou...@gmail.com>

>
> On Fri, Jul 17, 2009 at 11:21 AM, Mark
> Addleman<mark_addle...@bigfoot.com> wrote:
> >
> > On Jul 17, 2:35 am, Nicolas Oury <nicolas.o...@gmail.com> wrote:
> >> Hello,
> >>
> >> Can this construct handle higher-order functions?
> >
> > Nope :)
> >
> > Chouser brought up this point in IRC.  It's not even clear what the
> > syntax would look like.
>
> I suppose you could provide named-arg-aware high order
> functions with their own syntax.
>
>  (named-map subtract :from (range 0 30 3) :take (range 10))
>
> But you'd need everything -- filter, reduce, etc...
>
> There is something that can be done to make a normal call
> look more ... normal.  That is, instead of:
>
>  (named-call subtract :from 10 :take 2)
>
> you'd prefer:
>
>  (subtract :from 10 :take 2)
>
> Well, that's just a matter of writing a defn-named-args
> macro:
>
>  (defn-named-args subtract [from take] (- from take))
>
> Which would expand to something like:
>
>  (do
>    (defn subtract-func [from take] (- from take))
>        (defmacro subtract [& args]
>          `(named-call subtract-func ~...@args)))
>
> This actually came up in IRC too. :-)  Note it builds
> directly on the named-call macro you've already got.  Also
> note that it enforces the inability to use this 'subtract'
> in high order functions because it's now a macro.
>

Hi, though interesting, I sincerely think all this becomes a little bit too
complicated ... or maybe not general enough (starting to have to treat
"callable with named args" functions as second class citizens is a bad smell
and, maybe, not a good start in life for them ?)

Regards,

-- 
Laurent

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