Hi Jeremy, The 'find in collection' function is 'filter', so one way to write find the first match would be like: user=> (first (filter (partial = 25) (iterate inc 20))) 25 Filter is lazy itself so in this example I believe minimum execution is forced.
Regarding your questions about lazy evaluation specifically, I will refer you to: http://clojure.org/lazy Regards, Tim. On Jul 27, 2:54 am, Jeremy Gailor <jer...@infinitecube.com> wrote: > I have this very trivial function: > > (defn find-me [n] > (loop [coll (iterate inc 20)] > (if (= (first coll) n) > n > (recur (next coll))))) > > Let's leave out the problem that the loop may never end. My question is the > sequence that's bound to coll in the loop will only generate the next digit > in the sequence every time (first coll) is called? How does the evaluation > of (next coll) as the next loop parameter affect this? Is it just passing > the function (next coll) into the next loop iteration as an argument, and > then is that argument being evaluated when (first coll) is called again? > Is there another way I should be doing this sort of "look through a sequence > of elements until you find an element you are looking for, then return it". > I'm just learning Clojure so I'm not sure how to port over a very trivial > operation in another language here while working in a Clojure (functional) > style. I tried using (take-while) but it returns before I get the element > I'm looking for. > > Thanks for the help. > > - Jeremy --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en -~----------~----~----~----~------~----~------~--~---
