Very basic question. What's the idiom for producing a new seq wherein
each val is based on pairs from an existing seq, e.g.:
; add together n0 n1, n1 n2, n2 n3, etc.
[1 2 3 4 5 6]
; giving...
[3 5 7 9 11]
The verbose way would be something like:
(loop [s origSeq n [ ])
(let [a (first origSeq)
b (second origSeq)]
(if (nil? b)
n
(recur (rest origSeq) (conj n (+ a b))))))
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