Hi, We can define filter using foldr as under: filter1 p = foldr (\x xs -> (if (p x) then (x:xs) else xs)) []
Can we define filter using foldr but in pointfree style? How? Thanks -DM -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
