the only solution comes to mind is a two pass partition.

ie

(flatten (partition 1 2 dl)) for the first list
and (flatten (partition 1 2 (rest dl))) for the 2nd list.


2009/12/2 Konrad Kułakowski (kony) <kulakow...@gmail.com>:
> Recently I need something which works as "inverse of interleave"
>
> I did something like that:
>
> (defn unravel [expr-list]
>        (loop [flist () slist () tic-tac 0 olist expr-list]
>                (let [item (first olist)]
>                        (if (= item nil)
>                                (list flist slist)
>                                (if (= tic-tac 0)
>                                        (recur (concat flist (list item)) 
> slist 1 (rest olist))
>                                        (recur flist (concat slist (list 
> item)) 0 (rest olist)))))))
>
> Test:
>
> (def dl (interleave (iterate inc 1) ["A" "B" "C" "D" "E"]))
> (unravel dl)
>
> And the "classic" question is it possible to do it simple, more in a
> "functional manner", without explicit looping?
>
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