A slight modification, which I think avoids counting each collection
twice:
(defn append-val [val & colls]
(let [lengths (map count colls)
maxlen (apply max lengths)]
(map #(concat %1 (repeat (- maxlen %2) val)) colls lengths)
)
)
On Dec 23, 10:30 am, kyle smith <the1physic...@gmail.com> wrote:
> It's a little shorter if you unconditionally concat & repeat.
>
> (defn append-val [val & colls]
> (let [maxlen (apply max (map count colls))]
> (map #(concat % (repeat (- maxlen (count %)) val)) colls)))
>
> user> (apply map + (append-val 0 [1] [2 3] [4 5 6]))
> (7 8 6)
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