Hi, Am 09.01.2010 um 09:59 schrieb Dmitry Kakurin:
> Suppose I already have a function f that accepts 0 and 1 param: > (defn f > ([] 0) > ([ _ ] 1)) > > How do I extend it with additional version that takes 2 params? > Something like the following that does not override the original: > > (defn f [ _ _ ] 2) > > and makes all 3 work: > (f) > (f 1) > (f 1 2) This is not possible. You have to add the definition to the original one. Or – if you can't influence the original function definition – substitute your own: (def orig-f foo/f) (defn my-f ([] (orig-f)) ([x] (orig-f x)) ([_ _] 2)) (binding [foo/f my-f] (foo/f :a :b)) I suspect that you want to use that for a dirty hack. Why do you need that? Do you have some example code which demonstrates the problem? Sincerely Meikel
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