On May 4, 10:40 pm, Bryce <fiat.mo...@gmail.com> wrote: > I have a macro, deriv, that produces an expression, and I'd like to > create another macro that turns this into a function. So far I have > > (defmacro deriv-fn [fn-args exp v degree] > `(fn ~fn-args (deriv ~exp ~v ~degree))) > > Which of course doesn't work, since it considers the output of deriv > as a quoted list. So for instance > > (def f (deriv-fn [x y] (+ (* x y) (* 3 y)) y 1)) > > results in a function f of two variables which always returns '(+ x > 3) , rather than a function which evaluates (+ x 3). > > I feel like this is a nested backquote thing, where I could get it to > resolve at the correct point through artful use of ` and ~~, but I've > not been able to figure it out - am I on the right track? >
If deriv is a function that returns an expression, you need to do (defmacro deriv-fn [args exp v degree] `(fn ~args ~(deriv exp v degree))) -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
