On May 5, 2:54 pm, Robert Luo <robort...@gmail.com> wrote:
[snip]
> (repeated-seq #(range % 5) 0)
>
> the elements are: 0 1 2 3 4 4 5 6 7 8 8 ...
I think you mean,
(def s (repeated-seq #(range % (+ % 5)) 0) )
> However, I want to get rid of the duplicated index element (4, 8 etc),
> e.g.
> To produce 0 1 2 3 4 5 6 7 8 9
>
> But when I insert a rest into lazy-seq, the function just hung up.
> How can I make this happen?
I don't know if this is what you meant, but:
I think it depends on where you put the 'rest'
Try:
(defn repeated-seq
[f start]
(let [coll (f start)]
(concat coll (lazy-seq (rest (repeated-seq f (last coll)))))))
As opposed to
(defn repeated-seq
[f start]
(let [coll (f start)]
(concat coll (rest (lazy-seq (repeated-seq f (last coll)))))))
it isn't particularly efficient, though..
/Karl
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