For accessing groups in a match, you can use (re-matches). It will
always give the full match as the first element though:
user=> (re-matches date-regex "2011 1 13")
["2011 1 13" "2011" "1" "13"]
So to replicate the Ruby code's behavior maybe you'll just want (rest
(re-matches date-regex line)).
For ignoring case, putting (?i) at the beginning of the regex worked
for me. (re-find) should give you $1 just fine.
user=> (require '[clojure.string :as str])
nil
user=> (str/lower-case (re-find #"(?i)mon|tue|wed|thu|fri|sat|sun"
"asdf MON tue"))
"mon"
Hope this helps!
On Jan 13, 7:35 pm, Alex Baranosky <alexander.barano...@gmail.com>
wrote:
> So I am converting some Ruby code I have into CLojure for practice/fun and I
> am having trouble finding info via Google.
>
> I want to take something like this from Ruby and do it in Clojure:
>
> DATE_REGEX = /^\s*(\d{4})\s+(\d{1,2})\s+(\d{1,2})/
>
> token =~ DATE_REGEX
> [$1, $2, $3]
>
> So far my best guess has been:
>
> (defonce date-regex #"^\s*(\d{4})\s+(\d{1,2})\s+(\d{1,2})")
> (re-find date-regex line)
>
> but I'm not sure how to access $1, $2, and $3
>
> Another example I'd like to convert is this:
>
> DAYS_OF_WEEK_REGEX = /^\s*(#{Date::DAYS_OF_WEEK.join('|')})/i
>
> token =~ DAYS_OF_WEEK_REGEX
> $1.downcase.to_sym
>
> Best attempt is:
>
> (defonce days-of-week-regex #"mon|tue|wed|thu|fri|sat|sun(?i)")
> (re-find days-of-week-regex line)
>
> Here I'd love to know the syntax for ignore-case, along with how to access $1.
>
> Thanks,
> Alex
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