Interesting. Here is my attempt.

(defn enmap [args]
  (let [[fs & res] (reverse args)]
    (reduce (fn [v k] (hash-map k v)) fs res)))

> (enmap [1 2 3 4 {5 6 7 8}])
=> {1 {2 {3 {4 {5 6, 7 8}}}}}


>(let [[tail more] ((juxt last (comp reverse butlast)) [1 2 3 4 {5 6 7 8}])]
> (reduce #(hash-map %2 %1) tail more))
I still cannot understand what is going on in this code. juxt always
make my head crashed.

Thanks.

2011/3/11 Damien Lepage <damienlep...@gmail.com>:
> Hi
>
> I wrote a function to transform a variable number of arguments into embedded
> maps.
> Here is what it does:
>> (enmap 1 2)
> {1 2}
>> (enmap 1 2 3)
> {1 {2 3}}
>> (enmap 1 2 3 4)
> {1 {2 {3 4}}}
>> (enmap 1 2 3 4 {5 6 7 8})
> {1 {2 {3 {4 {5 6, 7 8}}}}}
> Here is my implementation:
> (defn enmap [arg & args]
>   (if-let [more (butlast args)]
>       (let [k (last more), v (last args)]
>         (if-let [even-more (butlast more)]
>           (apply enmap arg (concat even-more (list (hash-map k v))))
>           (enmap arg (hash-map k v))))
>       (apply hash-map arg args)))
> Two things bother me:
>
> Is there a way to make this function less complicated? without recursion
> maybe?
> Is there something simpler than (concat even-more (list (hash-map k v)) to
> append an element at the end of a sequence?
>
> Thanks
> --
> Damien
>
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