Hi all,
for testing my FunQL clojure graph query language against another query
language (GReQL), I want to write tests like that:
(defcomparisontest class-count-restricted (gbjg)
;; GReQL version
"count(V{ClassDefinition})"
;; FunQL variant 1
(vcount (gbjg) :cls 'ClassDefinition)
;; FunQL variant 2
(count (vseq (gbjg) :cls 'ClassDefinition)))
So you provide the name of the test, the graph the query is evaluated
on, a GReQL reference query, and arbitrary many FunQL forms that have to
calculate the exact same result.
I had such a macro that expects exactly one funql form, but while trying
to extend that to arbitrary many funqls, I've reached the limit of my
macro foo.
That's what I have come up with:
(defmacro defcomparisontest
"Define a GReQL/FunQL comparison test with name n on graph g that asserts the
equality of the results evaluating greql and all funqls."
[n g greql & funqls]
`(deftest ~n
~g ;; ensure the graph is loaded, if it is given as memoized function.
(println "####################################################")
(println "Comparison test:" ~(name n))
(let [gr# (do
(print "GReQL evaluation time:")
(jvalue-unpack (time (greql-eval ~g ~greql))))]
(doseq [funql# '~funqls]
(print "FunQL evaluation time:")
(is (= gr#
(time (let [r# funql#]
(if (instance? clojure.lang.LazySeq r#)
(doall r#)
r#)))))))))
Here, the problem is that the comparison compares the evaluation result
of the greql query against gr# the unevaluated funql form.
So I replaced the "(let [r# funql#]" with "(let [r# (eval funql#)]", but then
I seem to have namespace issues. I get errors like
java.lang.Exception: Unable to resolve symbol: vcount in this context
java.lang.Exception: Unable to resolve symbol: vseq in this context
which both are functions defined in funql.core, which my funql.test.core
namespace uses; (:use [funql.core] :reload) in the ns definition.
Could anyone with some advanced macro foo enlighten me how to do it
right?
By the way: in general, I would prefer if the expansion would contain a
sequence of (do ...) blocks with one assertion, one for each funql in
funqls, instead of the doseq.
Thanks a bunch in advance!
Tassilo
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