My observation is best distilled with the following definition of a function in Clojure 1.2:
user=> (defn id [x] (list id x)) #'user/id Interstingly, (id 7) and (eval (id 7)) result in different instances of function id as the number after the '@' char unveils: user=> (id 7) (#<user$id user$id@53797795> 7) user=> (eval (id 7)) (#<user$id user$id@2de12f6d> 7) Consequently, the following comparison leads to false: user=> (= (id 7) (eval (id 7))) false Why is the instance relevant to '='? What is the precise semantics of two values being equal in Clojure? Dominikus (Remark: In Scheme, the use of 'eqv?' returns also #f, but the less restrictive 'equal?' does not and returns #t.) -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
