In 1.3 the function will (eval) to itself: Clojure 1.3.0-alpha6 user=> (defn id [x] (list id x)) #'user/id user=> (id 7) (#<user$id user$id@3411a> 7) user=> (eval (id 7)) (#<user$id user$id@3411a> 7) user=> (= (id 7) (eval (id 7))) true
On May 5, 6:04 am, Dominikus <dominikus.herzb...@gmail.com> wrote: > My observation is best distilled with the following definition of a > function in Clojure 1.2: > > user=> (defn id [x] (list id x)) > #'user/id > > Interstingly, (id 7) and (eval (id 7)) result in different instances > of function id as the number after the '@' char unveils: > > user=> (id 7) > (#<user$id user$id@53797795> 7) > user=> (eval (id 7)) > (#<user$id user$id@2de12f6d> 7) > > Consequently, the following comparison leads to false: > > user=> (= (id 7) (eval (id 7))) > false > > Why is the instance relevant to '='? What is the precise semantics of > two values being equal in Clojure? > > Dominikus > > (Remark: In Scheme, the use of 'eqv?' returns also #f, but the less > restrictive 'equal?' does not and returns #t.) -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
