Hi,
I'm clear on what I want ;) (something new to me), but I'm not clear on how
to get there. I'd like to compare str1 and str2, if at least one of the
letters in str1 is in str2. I'm thinking that if I can convert str1 and str2
to sets, then I can use the set intersection operation. It probably doesn't
matter here if the sets contain characters or symbols?
Tuba
On Mon, Jul 18, 2011 at 10:31 PM, Benjamin Esham <bdes...@gmail.com> wrote:
> Tuba Lambanog wrote:
>
> > Tuba Lambanog wrote:
> >
> > > Hello, My apologies for this newbie question. I couldn't find a way to
> > > convert a string to a set, thus:
> > >
> > > "abc" => #{a b c}
> >
> > (set "abc") gives me #{\a \b \c}. I'm expecting instead: #{a b c}
>
> Hi Tuba,
>
> Are you quite sure that #{\a \b \c} is not what you want? In Clojure's
> notation, a backslashed character [more or less] refers to a
> single-character string--something akin to the char type from C. Hence \a
> is
> the character a. On the other hand #{a b c} is a set containing three
> Clojure symbols, which is probably not what you want.
>
> (If you want to be using a, b, and c as some kind of identifiers, take a
> look at keywords.)
>
> --
> Benjamin D. Esham | bdes...@gmail.com | www.bdesham.info
> How to Ask Questions the Smart Way, by Eric S. Raymond:
> http://catb.org/~esr/faqs/smart-questions.html
>
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