Hi,
Am 14.09.2011 um 16:54 schrieb octopusgrabbus:
> (defn skl
> [tree]
> (map skl (filter seq? tree)))
>
Is that what you want?
(defn skl
[tree]
(loop [output []
tree (seq tree)]
(if tree
(let [fst (first tree)]
(if (seq? fst)
(recur (conj output (skl fst)) (next tree))
(recur output (next tree))))
output)))
Sincerely
Meikel
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