(take-while (complement nil?) (repeatedly myfunc)) On Oct 25, 4:07 pm, rugby_road <cabjh...@embarqmail.com> wrote: > I have a function without arguments which returns a big,complex object > repeatedly until it returns nil. That is to say that the function > will produce a sequence of objects, but I don't know how many. I want > to call the generator as a lazy sequence but how do I make such a > thing? > > Currently I am doing something like this: > > (loop [i (myfunc)] > (if (nil? i) nil ;; we are done here > (let > ...do a bunch of stuff to i > (recur (myfunc))) > > This works okay, but leaves that recur statement dangling at the end > of the routine. What I would like to do is the cleaner: > > (doseq [ i (myseq)] > ...do a bunch of stuff to i) > > I have tried using (def myseq (repeatedly (myfunc))), but the > repeatedly doesn't seem to ever end. I have tried having myfunc > return a nil, or a [] but it just keeps repeating the final end value > of nil or []. > > How would you make such a terminating sequence? > Is there a special final value myfunc must return so that the sequence > ends gracefully? > Or is this just an abuse of the concept of a sequence and I should > just stick to the loop? > > thanks > Blake
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