Thanks for the answsers!
Jay's last answer is just what I was looking for.
thanks,
Sam
2012/1/14 Jay Fields <j...@jayfields.com>
> this seems easier...
>
> user=> (map str "abc")
> ("a" "b" "c")
>
> Though the original question says a list to a string and the example shows
> a string to a list (of symbols)
>
> user=> (apply str ["a" "b" "c"])
> "abc'
>
> But, the example is looks like it wants
>
> user=> (map (comp symbol str) "abc")
> (a b c)
>
> Hopefully one of those is what you're looking for.
>
> Cheers, Jay
>
> On Jan 14, 2012, at 1:01 PM, dennis zhuang wrote:
>
> You can do this
> > ((comp #(map str %) seq) "abcdef")
> ("a" "b" "c" "d" "e" "f")
>
> 2012/1/15 Bruce Durling <b...@otfrom.com>
>
>> Sam,
>>
>> Strings can be turned into sequences with seq.
>>
>> > (seq "foo")
>> (\f \o \o)
>>
>> The backslashes are because f o and o are character literals.
>>
>> cheers,
>> Bruce
>>
>> On Sat, Jan 14, 2012 at 10:13, Samuel Lê <samuel...@gmail.com> wrote:
>> > Hi,
>> >
>> > I was wondering if there was a function to convert a list into a string,
>> > something like:
>> > (string-to-list "abcde") ;; (a b c d e)
>> >
>> > thanks!
>> >
>> > Sam
>> >
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>
>
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