I am confused by this blog post: http://www.bestinclass.dk/index.clj/2009/09/php-vs-clojure-what-does-it-cost-to-be-old-school.html
In particular, I am confuse by this function: (defn log-dumper [a] (Thread/sleep *write-delay*) (let [sql-statements (let [tmp @*sql-buffer*] (ref-set *sql-buffer* []) tmp)] (doseq [stmt sql-statements] (run *mysql-connection* stmt)) (send-off *agent* log-dumper))) It looks like "a" is being passed in as an argument to the function. But at the end of the function, *agent* is being passed into the function again. I don't see a point in this function where "a" is magically transformed into *agent*. I'm under the impression that this same agent is suppose to be sent, over and over again, every 5 minutes, for all eternity, into the function. But if the function is suppose to send the same agent to itself, 5 minutes in the future, then I would think that if the argument is named "a" then "a" is what would be send-off to the function again. The blog post says: ""send-off" myself (the *agent* is the thread) to the same function again, ie. keep running." How does this work? How does the final line know that *agent* is the "a" that was passed in as an argument? -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en