On Fri, Oct 26, 2012 at 8:39 PM, Stephen Compall <stephen.comp...@gmail.com> wrote: > On Fri, 2012-10-26 at 09:06 -0700, Brian Craft wrote: >> First, do monads provide a generic solution, so I can apply >> f(g(h(x)))? > > Yes. control.algo.monads provides it as m-chain.
Can you expand on this? If the functions are f :: a -> b g :: c -> d h :: e -> j [renamed from "f"] and "you'd like to chain [them] like f(g(h(x))), but you can't because b is a different type from c and d is a different type from e.", how does m-chain help? I would have expected, given the "b is a different type from c" thing, that the chaining would go h(g(f(x)), but it's not as if that helps, unless the types work out like: b ~ m c d ~ m e in which case f >=> g >=> h :: a -> j works fine (assuming j is a monadic value). But as a general matter I don't see how monadic composition solves the problem. -- Ben Wolfson "Human kind has used its intelligence to vary the flavour of drinks, which may be sweet, aromatic, fermented or spirit-based. ... Family and social life also offer numerous other occasions to consume drinks for pleasure." [Larousse, "Drink" entry] -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
