As I tested, looks like when either of the args are double ie. 1.0 instead
of 1
then the code that checks for and shows divide by zero is not reached,
which is this code:
static public Number divide(Object x, Object y){
Ops yops = ops(y);
if(yops.isZero((Number)y))
throw new ArithmeticException("Divide by zero");
return ops(x).combine(yops).divide((Number)x, (Number)y);
}
On Tue, Oct 30, 2012 at 3:52 PM, Tim Olsen <t...@brooklynpenguin.com> wrote:
> Hello Clojurians.
>
> Normally by some IEEE floating-point standard, division by 0.0 should
> give Infinity (or NaN if the divisor is also 0.0). This is the case
> when using primitive doubles in clojure:
>
> (/ 1.0 0.0)
> => Infinity
>
> And even when using boxed Doubles in java:
>
> public class BoxedDoubleDivideZero {
>
> public static void main(String[] args) {
> Double a = new Double(4.0);
> Double b = new Double(0.0);
>
> System.out.println(a/b);
> }
> }
>
> $ javac BoxedDoubleDivideZero.java
> $ java BoxedDoubleDivideZero
> Infinity
>
> But it is not the case when using boxed Doubles in clojure:
>
> (/ (Double. 1.0) (Double. 0.0))
> ArithmeticException Divide by zero clojure.lang.Numbers.divide
> (Numbers.java:156)
>
> Is this considered a bug or feature?
>
> Thanks,
> Tim
>
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--
I may be wrong or incomplete.
Please express any corrections / additions,
they are encouraged and appreciated.
At least one entity is bound to be transformed if you do ;)
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