It might mean you're probably having a typo somewhere you're trying to
extend a protocol like so:

(defprotocol IFoo
  (foo [x]))

(defrecord MyFoo [x y]
  IFoo
  (fooo [x] x)) ; note misspelled foo

;; CompilerException java.lang.IllegalArgumentException:
;; Can't define method not in interfaces: fooo, compiling:(NO_SOURCE_PATH:1)

Correct? K.

On 18 November 2012 21:16, Jim - FooBar(); <[email protected]> wrote:
> I'm struggling to find an explanation for this...
>
> what on earth is this? what does it mean?
>
> Can anyone clarify where this exception comes from?
>
> Jim
>
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