Thanks both - (and yes I did mean brackets - oops).
On 19 Jan 2013, at 18:26, Sven Johansson <johansson.s...@gmail.com> wrote:
> On Sat, Jan 19, 2013 at 7:02 PM, Colin Yates <colin.ya...@gmail.com> wrote:
> user=> (defn stream1 [] repeatedly create-user)
>
> This function invokes neither repeatedly nor create-user. It pointlessly
> refers to repeatedly and then returns a reference to the create-user function.
> Which is function and not a sequence, which is why you cannot take n from it.
>
> user=> (defn stream2 [] (repeatedly create-user))
>
> This function invokes repeatedly with a reference to create-user and returns
> a lazy-sequence, which you can take n from.
>
> > In other words, what effect does wrapping the function body in quotes
> > actually do?
>
> By quotes I assume you mean ()'s. The answer is above. in stream1 you are
> simply refering to functions. Without the ()'s
> you're not invoking anything.
>
> Compare:
> user> create-user
> #<user$create_user user$create_user@3f8ecde>
>
> to:
>
> user> (create-user)
> {:id 1}
> user>
>
> /S
>
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