yes, I believe I can just make a list of the greatest common factors and
then multiply them out to get the number rather than iterating through 2
through n. Still, I'm curious about the performance difference, since
all three are running on the same JVM and ultimately are all compiled
down to java byte code, you would expect that a similar algorithm would
produce similar results across the three.
On 02/03/2013 07:29 AM, Jules wrote:
If your goal is just to make it fast, then you should use a different
algorithm, e.g.
(defn bump-up "Bump up n by a multiple of x until greater than or
equal to k." [n x k] (if (>= n k) n (recur (+ n x) x k)))
(defn bump-up-fast "Bump up n by a multiple of x until greater than
or equal to k in O(1)." [n x k] <exercise for the reader>)
(defn lcm "Compute the least common multiple of a and b." [a b] (loop
[n a k b] (cond (< n k) (recur (bump-up n a k) k) (> n k) (recur n
(bump-up k b n)) (= n k) n)))
(defn smallest-multiple-of-1-to-n [n] (reduce lcm (range 1 (+ n
1))))
On Sunday, February 3, 2013 3:28:09 AM UTC+1, Alexandros Bantis
wrote:
Hello all. I'm working through the Project Euler problems in Java,
Scala, & Clojure (trying to learn all three?!?). I notice that for
one particular problem, I use--more or less--a similar algorithm for
all three, but the clojure code runs about 20-30 times slower than
the java/scala versions. Does anyone have any idea why this might be?
It strikes me that it might have something to do with every? but I
don't know because I'm a newbie with Clojure.
http://stackoverflow.com/questions/14668272/what-can-i-do-to-speed-up-this-code
<http://stackoverflow.com/questions/14668272/what-can-i-do-to-speed-up-this-code>
thanks,
alex
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