In this line: (map (if even? (fn [num _] (identity spans)) str) some-seq1 some-seq2)
you appear to involve *identity* in a way that makes no sense since (identity spans) is just spans. You also don't involve the *num* argument at all; but maybe you meant (map (if even? (fn [num _] num) str) some-seq1 some-seq2) Then I'd see what you mean, even though I wouldn't call that function * identity* because it clearly does something more specialized than a no-op: it *ignores* the element coming from some-seq2. It would be quite confusing to see a function named *identity* do that. On Wednesday, February 27, 2013 1:39:54 PM UTC+1, Jim foo.bar wrote: > > On 27/02/13 12:35, Marko Topolnik wrote: > > it is a function that transforms its argument into itself. It is > > useful in the context of higher-order functions where it plays the > > role of a no-op > > that is exactly what I'm trying to do..a no-op based on some > condition...Though, I can see why it would be confusing to just return > the first arg...what exactly makes no sense? > > Jim > -- -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en --- You received this message because you are subscribed to the Google Groups "Clojure" group. To unsubscribe from this group and stop receiving emails from it, send an email to clojure+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
