If (map find-records query-parts) is returning this expression:
(({:a2p-id "1", :dh-uuid "abc-def-ghi-klm"} {:a2p-id "2", :dh-uuid
"def-ghi-klm-opq"} {:a2p-id "3", :dh-uuid nil}) ({:a2p-id "1", :dh-uuid
"abc-def-ghi-klm"} {:a2p-id "2", :dh-uuid "def-ghi-klm-opq"} {:a2p-id "3",
:dh-uuid nil}))
then especially note the double parentheses. That is a list (or sequence),
whose first element is a list (or sequence) of maps. You can use (first
(map find-records query-parts)) to get the inner list.
Andy
On Sat, May 25, 2013 at 4:21 AM, Mond Ray <mondraym...@gmail.com> wrote:
> I am missing something obvious... I get a list of maps back from a
> function and I want to find the elements with nil
>
> (({:a2p-id "1", :dh-uuid "abc-def-ghi-klm"} {:a2p-id "2", :dh-uuid
> "def-ghi-klm-opq"} {:a2p-id "3", :dh-uuid nil}) ({:a2p-id "1", :dh-uuid
> "abc-def-ghi-klm"} {:a2p-id "2", :dh-uuid "def-ghi-klm-opq"} {:a2p-id "3",
> :dh-uuid nil}))
>
> I try the select function but it has no effect ... same list
>
> (set/select #(not (:dh-uuid %)) (map find-records query-parts))
>
> also tried the previously working example... same list
>
> (filter #(not (:dh-uuid %)) (map find-records query-parts))
>
> I am assuming that I am not indexing into each of the maps but I cannot
> remember or find out how to do this ... all examples only show one map
>
> Thanks
>
> Ray
>
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