Very likely Juan, as seen here:
(let [agents (map agent (range 30 35))]
(doseq [a agents]
(send a + 100)
(println @a))
(doseq [a agents]
(println @a)))
For me that prints:
30
31
32
33
34
130
131
132
133
134
but I suspect that's more luck that anything since there's no reason
the agent operations need to have finished before the second println.
Kuba, as a separate issue, why are you trying to intern all those
symbols? It's not very idiomatic.
Sean
On Tue, Aug 20, 2013 at 4:49 PM, juan.facorro <juan.faco...@gmail.com> wrote:
> If on the println you don't see the value updated, it's probably because the
> operation sent to the agent wasn't applied yet.
>
> Add a (Thread/sleep 500) in between the send and println expressions and
> you'll see the expected agents'.
>
> Cheers,
>
> JF
>
>
> On Wednesday, August 21, 2013 12:21:59 AM UTC+1, Kuba Roth wrote:
>>
>> Hi there,
>> I've got a range of values and I'd like to run agents for each value per
>> thread. For some reason I've got only one agents being updated.
>> Not sure what's wrong here but I suspect must be doing something terrible
>> stupid...
>>
>> Thanks!
>>
>> (doseq [s (range 30 35)]
>> ;(println (format "_%s" s))
>> (intern *ns* (symbol (format "_%s" s) ) (agent s)) ;; set
>> initial value
>> (send @(intern *ns* (symbol (format "_%s" s))) + 100) ;; send
>> agent and update value
>> (println @(intern *ns* (symbol (format "_%s" s)) )) ;; deref
>> )
>
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