Dennis Haupt <[email protected]> writes:
> (defn fib-n [n]
> (let [fib (fn [a b] (cons a (lazy-seq (fib b (+ b a)))))]
> (take n (fib 1 1))))
>
> can't i do a recursion here? how can i achieve this without doing an
> "outer defn"?
You just need to give the anonymous function a name it can use to refer
to itself for (non-tail) recursion:
(defn fib-n [n]
(let [fib (fn fib [a b] (cons a (lazy-seq (fib b (+ b a)))))]
(take n (fib 1 1))))
-Marshall
--
--
You received this message because you are subscribed to the Google
Groups "Clojure" group.
To post to this group, send email to [email protected]
Note that posts from new members are moderated - please be patient with your
first post.
To unsubscribe from this group, send email to
[email protected]
For more options, visit this group at
http://groups.google.com/group/clojure?hl=en
---
You received this message because you are subscribed to the Google Groups
"Clojure" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
For more options, visit https://groups.google.com/groups/opt_out.
