In fact, you mix the output in the REPL and the result of the map function.
The result of the map call is (1 2 3 4 5), but you have the print display
is managed by the repl and is done when is done :)

If you want as result a string with the negative value, you must do:

(map #(str "-" %) '(1 2 3 4 5))



2013/8/28 <ljcppu...@gmail.com>

> Hi
>
> user=>  (def r (map #(do (print "-") %) '(1 2 3 4 5)))
> #'user/r
> user=> (println r)
> (--1 -2 -3 -4 5)
> nil
>
> On Wednesday, August 28, 2013 4:57:49 PM UTC+8, Christian Sperandio wrote:
>
>> Hi,
>>
>> Try just one thing:
>>
>> (def r (map #(do (print "-") %) '(1 2 3 4 5)))
>>
>> And after, do (println r)
>>
>> What do you get?
>>
>>
>>
>>
>>
>>
>>
>> 2013/8/28 <ljcp...@gmail.com>
>>
>>> Hi
>>>
>>> (map #(do (print "-") %) '(1 2 3 4 5))
>>> I think the result should be (-1 -2 -3 -4 -5), but it is (--1 -2 -3 -4
>>> 5), it's difficult to understand,
>>> Can someone give answer?
>>>
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