Hi, Clojure's compile unit is one toplevel form. Therefore
(intern 'user 'bob3 3) bob3 works, while (is (do (intern 'user 'bob2 2) bob2)) does not, because the former are two compilation units while the latter is only one. (Note: (do ...) is a special case. (do (intern 'user 'bob3 3) bob3) should actually work.) Then there is a separate effect in that def immediately creates the Var when encountered during compilation. That explains why the def variant works as well. (And as a side-note: that's also why you don't do (defn foo [] (def a ...) ...)) Kind regards Meikel -- -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en --- You received this message because you are subscribed to the Google Groups "Clojure" group. To unsubscribe from this group and stop receiving emails from it, send an email to clojure+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
