On Oct 23, 2013, at 14:34 , Mark Engelberg <mark.engelb...@gmail.com> wrote:
> Another example of why this has more to do with the hashing of sets, than
> underlying elements:
> => (hash #{#{1 2} 3})
> 6
> => (hash #{#{1 3} 2})
> 6
The hash-combining function for sets must be commutative. But in order for the
hashes of #{#{1 2} 3} and #{#{1 3} 2} to be unequal, it must also be
non-associative. That's possible, but I'm not sure what would be a good
candidate function. Something involving averaging, perhaps?
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