Hi Edward,

I believe the return value of your expression is (nil nil nil nil ...), but
the printlns are forced just after the ( is printed.

Thanks,
Ambrose


On Mon, Nov 25, 2013 at 9:14 PM, <edw...@kenworthy.info> wrote:

> Some (println) weirdness (board is a vector to vectors):
>
> (println (board 0))
> (println (board 1))
> (println (board 2))
> (println (board 3))
> (println (board 4))
> (println (board 5))
> (println (board 6))
> (println (board 7))
>
> Works as I would expect, printing to the console.
>
> However:
>
> (for [row board]
>     (println row))
>
> Doesn't: the output from println is part of the result of evaluating the
> for (along with a slew of nils).
>
> ([:empty :empty :empty :empty :empty :empty :empty :empty]
> [:empty :empty :empty :empty :empty :empty :empty :empty]
> [:empty :empty :empty :empty :empty :empty :empty :empty]
> [:empty :empty :empty :white :black :empty :empty :empty]
> [:empty :empty :empty :black :white :empty :empty :empty]
> [:empty :empty :empty :empty :empty :empty :empty :empty]
> [:empty :empty :empty :empty :empty :empty :empty :empty]
> [:empty :empty :empty :empty :empty :empty :empty :empty]
> nil nil nil nil nil nil nil nil)
>
> Any idea why there is any difference at all between the two? The only
> thing I can think of is for's lazy evaluation but I don't see how.
>
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